What is the average power dissipation in a series RC circuit if R = 6.35 kΩ,C = 2.64 µF,and V = (192 V)cos 115t?
A)2.29 W
B)5.81 W
C)2.90 W
D)3.23 W
E)6.47 W

Question

Quizplus · Accepted Answer

The average power dissipation in a series RC circuit is given by $P = \frac{V_{rms}^2}{R}$, where $V_{rms}$ is the root mean square value of the voltage, and $R$ is the resistance. The given voltage is $V = (192 V)\cos 115t$, so the peak voltage $V_{peak}$ is 192 V. The $V_{rms}$ is $V_{peak}/\sqrt{2}$, which is $192/\sqrt{2}$ V. Plugging the values into the formula gives $P = \frac{(192/\sqrt{2})^2}{6350}$ (converting 6.35 kΩ to ohms), which calculates to approximately 2.29 W.

What Is the Average Power Dissipation in a Series RC