A rectangular loop (area = 0.250 m²)turns in a uniform magnetic field with B = 0.210 T.At an instant when the angle between the magnetic field and the normal to the plane of the loop is π/2 rads and increasing at the rate of 0.530 rad/s,what is the magnitude of the emf induced in the loop? A)5.25E-2 V B)zero C)2.78E-2 V D)9.91E-2 V E)1.47E-2 V

Question

Quizplus · Accepted Answer

The formula for the induced emf in a rotating loop in a magnetic field is given by:
ε = B*A*(dθ/dt)*cos(θ) where B is the magnitude of magnetic field, A is the area of the loop, dθ/dt is the rate of change of the angle between the magnetic field and the normal to the plane of the loop, and θ is the initial angle between the magnetic field and the normal to the plane of the loop.

Substituting the given values, we get:
ε = (0.210 T) * (0.250 m2) * (0.530 rad/s) * cos(π/2) = 0.0278 V

Therefore, the magnitude of the induced emf in the loop is 0.0278 V or 2.78E-2 V, which is option C.

A Rectangular Loop (Area = 0