A wire loop of radius 0.250 m is placed in a uniform magnetic field of magnitude 0.740 T. The field is directed perpendicular to the plane of the loop.
-If the area of the loop increases at a rate of area 1.50 * 10^-3 m²/s,what is the magnitude of the emf induced in the coil?

Question

Quizplus · Accepted Answer

The magnitude of the emf induced in the coil can be calculated using Faraday's law of electromagnetic induction, which states that the induced emf (ε) in a circuit is equal to the rate of change of the magnetic flux through the circuit. The formula for emf is ε = -dΦ/dt, where Φ is the magnetic flux. The magnetic flux (Φ) through the loop is given by Φ = B*A, where B is the magnetic field strength and A is the area of the loop. Given that the area of the loop increases at a rate of 1.50 x 10^-3 m^2/s, and the magnetic field strength is 0.740 T, the rate of change of magnetic flux dΦ/dt = B * dA/dt = 0.740 T * 1.50 x 10^-3 m^2/s = 1.11 x 10^-3 T*m^2/s = 1.11 mV. Therefore, the magnitude of the induced emf is 1.11 mV.

A Wire Loop of Radius 0