The ammeter shown in the figure reads 4.4 A,R 1 = 7.0 Ω,R 2 = 5.0 Ω,and R 3 = 2.0 Ω.
-What is $\varepsilon$?
A)34 V
B)-9.8 V
C)22 V
D)-2.2 V

Question

The ammeter shown in the figure reads 4.4 A,R 1 = 7.0 Ω,R 2 = 5.0 Ω,and R 3 = 2.0 Ω. 
-What is $\varepsilon$?
A)34 V 
B)-9.8 V 
C)22 V 
D)-2.2 V

Quizplus · Accepted Answer

Using Kirchhoff's voltage law, we can write:
F1F1F1S1F1F1F10 - RS1U1B11S1U1B0(I1I1I1S1U1B0) - RS1U1B12S1U1B0(I1I1I1S1U1B0) - RS1U1B13S1U1B0(I1I1I1S1U1B0) = 0

Substituting the given values, we get:
F1F1F1S1F1F1F10 - (7.0 Ω)(4.4 A) - (5.0 Ω)(4.4 A) - (2.0 Ω)(4.4 A) = 0
F1F1F1S1F1F1F10 = 34 V

Therefore, the answer is A.

The Ammeter Shown in the Figure Reads 4 ε\varepsilonε ? A)34 V B)-9

The Ammeter Shown in the Figure Reads 4 $\varepsilon$ ?
A)34 V
B)-9