A battery with an emf of 12.0 V has a terminal voltage of 11.25 V when the current is 3.15 A.What is the load resistance,R?
A)0.238 Ω
B)2.34 Ω
C)3.57 Ω
D)7.38 Ω

Question

Quizplus · Accepted Answer

We can use Ohm's law and Kirchhoff's loop rule to solve for the load resistance.

From Ohm's law, we know that V = IR, where V is the voltage, I is the current, and R is the resistance.

From Kirchhoff's loop rule, we know that the emf of the battery (E) minus the voltage drop across the load (IR) equals the terminal voltage (V).

So, we can set up the following equations:

E = IR + V
12.0 V = 3.15 A * R + 11.25 V
0.75 V = 3.15 A * R
R = 0.75 V / 3.15 A
R = 0.238 Ω

Therefore, the answer is choice C, 3.57 Ω is not the correct answer.

A Battery with an Emf of 12