A point charge of +4.0 μC is located at the origin of a coordinate system and a second point charge of −6.6 μC is at x = 1.7 m.What is the electric potential at the x = 0.85 m point? (k_e = 8.99 × 10⁹ N⋅m²/C²) A)-2.9 × 10⁴ V B)-27 × 10⁴ V C)−56 × 10⁴ V D)-2.7 × 10⁴ V E)56 × 10⁴ V

Question

Quizplus · Accepted Answer

The electric potential at a point due to a point charge can be calculated using the equation:

V = kQ/r

where k is the Coulomb's constant (8.99 × 10^9 N·m^2/C^2), Q is the charge of the point charge, and r is the distance between the point charge and the point where electric potential is being measured.

Using this equation, we can calculate the electric potential at x=0.85 m as:

V = (8.99 × 10^9 N·m^2/C^2) * [(4.0 μC)/0.85 m - (6.6 μC)/1.85 m]
V = - 2.7 × 10^4 V = -2.7 × 10^14 V

Therefore, the best choice is D, with the calculated electric potential of -2.7 × 10^14 V at x=0.85 m.

A Point Charge of +4