A proton (+1.6 × 10−¹⁹ C)moves 20 cm on a path in the direction of a uniform electric field of strength 2.4 N/C.How much work is done on the proton by the electrical field? A)7.7E-20 J B)−7.7E-20 J C)1.8E-19 J D)−8.6E-20 J E)zero

Question

Quizplus · Accepted Answer

The work done on the proton by the electric field is calculated using the formula W = qEd, where q is the charge of the proton (1.6 × 10^-19 C), E is the electric field strength (2.4 N/C), and d is the distance moved (20 cm = 0.2 m). Thus, W = (1.6 × 10^-19 C)(2.4 N/C)(0.2 m) = 7.68 × 10^-20 J, which rounds to 7.7 × 10^-20 J.

A Proton (+1