The average distance of the electron from the proton in the hydrogen atom is 0.65 × 10−¹⁰ m.What is the electric field from the proton's charge at the location of the electron? (k_e = 8.99 × 10⁹ N⋅m²/C²,e = 1.6 × 10−¹⁹ C) A)3.4E+11 N/C B)5.4E+6 N/C C)5.2E+1 N/C D)2.2E-8 N/C E)1.0E-8 N/C

Question

Quizplus · Accepted Answer

The electric field $E$ from a point charge, like a proton, is given by $E = \frac{k|q|}{r^2}$, where $k = 8.99 \times 10^9 \, \text{N}\cdot\text{m}^2/\text{C}^2$, $q = 1.6 \times 10^{-19} \, \text{C}$ is the charge of the proton (or electron), and $r = 0.65 \times 10^{-10} \, \text{m}$ is the distance between the proton and the electron. Plugging these values into the formula gives $E = \frac{8.99 \times 10^9 \times 1.6 \times 10^{-19}}{(0.65 \times 10^{-10})^2} \, \text{N/C}$, which calculates to approximately $3.4 \times 10^{11} \, \text{N/C}$.

The Average Distance of the Electron from the Proton in the Hydrogen