An object moving in simple harmonic motion has an amplitude of 0.0450 m and a maximum acceleration of 40.0 m/s².What is the frequency of the system? A)14.9 Hz B)187 Hz C)4.75 Hz D)11.9 Hz E)1.80 Hz

Question

Quizplus · Accepted Answer

The maximum acceleration in simple harmonic motion is given by a = ω^2A, where A is the amplitude and ω is the angular frequency. Rearranging this equation gives ω = sqrt(a/A). Substituting the given values, we get: ω = sqrt(40.0 m/s^2 / 0.0450 m) = 31.6 rad/s. The frequency of the system is given by f = ω/2π, which gives: f = 31.6 rad/s / (2π) = 4.75 Hz (to two significant figures). Therefore, the correct answer is C.

An Object Moving in Simple Harmonic Motion Has an Amplitude