A refrigerator has a coefficient of performance of 3.0.When removing 2.7 × 10⁴ J from inside the refrigerator,how much energy is sent into the environment? A)9.0E+3 J B)3.6E+4 J C)8.1E+4 J D)1.1E+5 J E)4.8E+4 J

Question

Quizplus · Accepted Answer

The coefficient of performance (COP) for a refrigerator is defined as the ratio of the heat removed from the inside (Q_c) to the work input (W), COP = Q_c/W. The energy sent into the environment is the sum of the heat removed from the inside and the work input, which is Q_h = Q_c + W. Given COP = 3.0 and Q_c = 2.7 × 10^4 J, we can find W = Q_c / COP = (2.7 × 10^4 J) / 3.0 = 9.0 × 10^3 J. Therefore, the energy sent into the environment, Q_h = Q_c + W = 2.7 × 10^4 J + 9.0 × 10^3 J = 3.6 × 10^4 J.

A Refrigerator Has a Coefficient of Performance of 3