A worker pushes a sled with a force of 38.0 N over a level distance of 3.60 m.If a frictional force of 16.0 N acts on the wheelbarrow in a direction opposite to that of the worker,what net work is done on the wheelbarrow?
A)194 J
B)137 J
C)57.6 J
D)79.2 J
E)6.11 J

Question

Quizplus · Accepted Answer

The net force is the applied force minus the frictional force: 38.0 N - 16.0 N = 22.0 N. The net work done is the net force multiplied by the distance: 22.0 N * 3.60 m = 79.2 J.

A Worker Pushes a Sled with a Force of 38