A sled weighs 160 N.It is held in place on a frictionless 25.0° slope by a rope attached to a stake at the top;the rope is parallel to the slope.What is the normal force of the slope acting on the sled?
A)145 N
B)67.6 N
C)177 N
D)379 N
E)74.6 N

Question

Quizplus · Accepted Answer

The normal force can be calculated using the formula for the component of the weight perpendicular to the slope, which is $W \cos(\theta)$, where $W$ is the weight of the sled and $\theta$ is the angle of the slope. Given that the sled weighs 160 N and the slope is 25.0°, the calculation is $160 \cos(25.0°)$, which approximately equals 145 N.

A Sled Weighs 160 N