A baseball thrown from the outfield is released from shoulder height at an initial velocity of 29.1 m/s at an initial angle of 30.0° with respect to the horizontal.What is the maximum vertical displacement that the ball reaches during its trajectory?
A)10.8 m
B)21.6 m
C)32.4 m
D)14.4 m
E)28.8 m

Question

A baseball thrown from the outfield is released from shoulder height at an initial velocity of 29.1 m/s at an initial angle of 30.0° with respect to the horizontal.What is the maximum vertical displacement that the ball reaches during its trajectory?​
A)10.8 m
B)21.6 m
C)32.4 m
D)14.4 m
E)28.8 m

Quizplus · Accepted Answer

The maximum vertical displacement (height) can be found using the formula $h = \frac{v^2 \sin^2(\theta)}{2g}$, where $v$ is the initial velocity, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$). Plugging in the given values: $h = \frac{(29.1)^2 \sin^2(30^\circ)}{2 \times 9.8} \approx 10.8 \, \text{m}$.

A Baseball Thrown from the Outfield Is Released from Shoulder