A ball is pushed downhill with an initial velocity of 3.0 m/s.The ball rolls down a hill with a constant acceleration of 1.6 m/s².The ball reaches the bottom of the hill in 6.0 s.What is the ball's velocity at the bottom of the hill? A)10 m/s B)13 m/s C)16 m/s D)17 m/s

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Quizplus · Accepted Answer

The ball's velocity at the bottom of the hill can be calculated using the formula $v = u + at$, where $v$ is the final velocity, $u$ is the initial velocity (3.0 m/s), $a$ is the acceleration (1.6 m/s$^2$), and $t$ is the time (6.0 s). Plugging in the values, we get $v = 3.0 m/s + (1.6 m/s^2 \times 6.0 s) = 3.0 m/s + 9.6 m/s = 12.6 m/s$, which rounds to 13 m/s.

A Ball Is Pushed Downhill with an Initial Velocity of 3.0