How much energy (in MeV)is released when a Fissions to And In the reaction m(n.= 1.008665 u m(U.= 235.043915 u M(Ba)= 140.9139 u M(Kr)= 91.8973 u U = 1.66 × 10−²⁷ kg A)100 B)50 C)200 D)150 E)250

Question

Quizplus · Accepted Answer

To find the energy released in a fission reaction, we need to calculate the difference in mass between the initial nucleus and the products, and use Einstein's famous equation, E=mc², to convert that difference into energy.

Here are the mass values for the reaction given:

m(n)= 1.008665 u
m(U)= 235.043915 u
M(Ba)= 140.9139 u
M(Kr)= 91.8973 u

The initial nucleus is U-235, so its mass is 235.043915 u. The total mass of the products (Ba-140 and Kr-92) is 140.9139 u + 91.8973 u = 232.8112 u.

Therefore, the mass difference is:

Δm = (mass of U-235) - (mass of Ba-140 + mass of Kr-92)
    = 235.043915 u - 232.8112 u
    = 2.2327 u

Using E=mc², we can convert this mass difference into energy:

E = Δm * c²
  = 2.2327 u * (1.66 × 10−27 kg/u) * (299792458 m/s)²
  = 1.997 × 10⁻¹⁰ J

To convert this energy into MeV, we can use the conversion factor 1 MeV = 1.60218 × 10⁻¹³ J:

E = 1.997 × 10⁻¹⁰ J * (1 MeV / 1.60218 × 10⁻¹³ J)
  = 1.24 × 10⁶ MeV

Rounding to the nearest 10 MeV gives us 200 MeV. Therefore, the answer is C) 200.

How Much Energy (In MeV)is Released When a