What mass of silver nitrate is dissolved in 40.0 mL of a 0.400 M solution of silver nitrate?
A)0.272 g
B)2.72 g
C)27.2 g
D)272 g

Question

Quizplus · Accepted Answer

To calculate the mass of silver nitrate dissolved in the solution, we first need to determine the number of moles of silver nitrate present in 40.0 mL of the solution. We can use the formula:

moles = concentration x volume

where concentration is given as 0.400 M and volume is given as 40.0 mL (which we convert to liters by dividing by 1000):

moles = 0.400 M x 40.0 mL / 1000 mL/L = 0.016 mol

Next, we need to use the molar mass of silver nitrate (AgNO3) to convert moles to grams:

mass = moles x molar mass

The molar mass of AgNO3 is 107.87 g/mol. Thus:

mass = 0.016 mol x 107.87 g/mol = 1.726 g

Therefore, the mass of silver nitrate dissolved in the solution is 1.726 g, which is closest to answer choice B: 2.72 g (since the other answer choices are either too small or too large).

What Mass of Silver Nitrate Is Dissolved in 40