What is the molality of a solution prepared by dissolving 40.0 g of glucose (C₆H₁₂O₆)in 4.00 kg of water? A)0.0555 m B)10.0 m C)0.0100 m D)0.222 m

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Quizplus · Accepted Answer

Molality (m) is defined as the number of moles of solute per kilogram of solvent. The molar mass of glucose (C6H12O6) is calculated as follows: (12.01*6) + (1.008*12) + (16.00*6) = 180.16 g/mol. The number of moles of glucose is 40.0 g / 180.16 g/mol = 0.222 moles. Since the solvent is 4.00 kg (or 4.00 kg * 1 kg/1000g = 4.00 kg), the molality is 0.222 moles / 4.00 kg = 0.0555 m.

What Is the Molality of a Solution Prepared by Dissolving