How many units of AgNO₃ are present in 147g of this compound? A)4.15 10^-20 B)5.21 10²³ C)1.47 10²¹ D)6.96 10²³

Question

Quizplus · Accepted Answer

1 mole of AgNO₃ has a molar mass of 294.1 g/mol (107.87 g/mol for Ag, 14.01 g/mol for N, 15.99 g/mol for O, 32.06 g/mol for S, and 18.02 g/mol for H). To find the number of moles in 147g: moles = mass/molar mass moles = 147g/294.1 g/mol moles = 0.5 mol Since there is 1 unit of AgNO₃ per mole, the number of units in 0.5 mol is also 0.5. Therefore, the answer is B) 5.21 11ea7f51_1e85_e0a6_9ecd_9b4fa7d2aea9_TB4036_11 10²³

How Many Units of AgNO3 Are Present in 147g of This

How Many Units of AgNO₃ Are Present in 147g of This