An atom of zinc has a mass of 65.39 amu.One of its isotopes, ,has an 18.75% abundance.Since 1 amu = 1.6606 x 10-24 g,how many of atoms of this zinc isotope would be present in a 1.00 g sample of zinc?
A) 9.209 x 1021 atoms
B) 4.911 x 1022 atoms
C) 1.727 x 1021 atoms
D) 4.762 x 1021 atoms
Correct Answer:
Verified
Q83: Dalton's atomic model states that all atoms
Q84: Cations are electrically negative and anions are
Q85: The mass number of an atom is
Q86: The mass number of an ion that
Q87: The majority of the volume of an
Q89: The majority of the mass of an
Q90: One atomic mass unit is 1/12 the
Q91: Sulfur occurs naturally as four isotopes: 32S
Q92: The atomic number of an atom is
Q93: Select the hypothetical atom that could be
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents