When 20.0g of mercury is heated from 10.0^ºC to 20.0^º,27.6 J of energy are absorbed.What is the specific heat of mercury? A)0.725 J/g^ºC B)0.138 J/g^ºC C)2.76 J/g^ºC D)No correct answer is given

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat absorbed, $m$ is the mass, $c$ is the specific heat, and $\Delta T$ is the change in temperature. Plugging in the given values: $27.6 \, \text{J} = 20.0 \, \text{g} \cdot c \cdot (20.0 - 10.0) \, ^\circ\text{C}$. Solving for $c$ gives $c = 0.138 \, \text{J/g} \, ^\circ\text{C}$.

When 200g of Mercury Is Heated from 10