What is the specific heat of a solid that requires 124 J of heat to raise the temperature of 95.5g of the substance from 20.0^ºC to 25.0^ºC? A)2.6 J/g^ºC B)0.26 J/g^ºC C)1.4 J/g^ºC D)5.9 X 10⁴ J/g^ºC

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat added, $m$ is the mass, $c$ is the specific heat, and $\Delta T$ is the change in temperature. Rearranging for $c$, we get $c = \frac{q}{m\Delta T}$. Plugging in the given values: $c = \frac{124\,J}{95.5\,g \times (25.0 - 20.0)\,^\circ C} = \frac{124\,J}{95.5\,g \times 5\,^\circ C} = 0.26\,J/g\,^\circ C$.

What Is the Specific Heat of a Solid That Requires