Solve the triangle using the law of sines. Round sides to the nearest tenth. side a = 5 m
$\angle$A = 56°
$\angle$B = 41°
A). $\angle$C = 83° b $\approx$3.3 m
C $\approx$ 5.4 m
B). $\angle$C = 83° b $\approx$ 3.8 m
C $\approx$ 6.4 m
C). $\angle$C = 83° b $\approx$ 4.0 m
C $\approx$6.0 m
D). $\angle$C = 83° b $\approx$ 4.5 m
C $\approx$ 5.8 m

Question

Quizplus · Accepted Answer

We can use the law of sines to solve for side b and side c:

sin(56°)/5 = sin(41°)/b = sin(83°)/c

Solving for b, we get:

b = sin(41°) * (5/sin(56°)) ≈ 3.8 m

Solving for c, we get:

c = sin(83°) * (5/sin(56°)) ≈ 6.0 m

Therefore, the best choice is C, with the closest values to 3.8 m and 6.0 m.

Solve the Triangle Using the Law of Sines ∠\angle∠ A = 56°

Solve the Triangle Using the Law of Sines $\angle$ A = 56°