What is the pOH of an aqueous solution at 25.0 °C that contains 2.50 × 10^-4 M hydronium ion? A)3.60 B)4.00 C)2.50 D)10.4 E)7.00

Question

Quizplus · Accepted Answer

The pOH of a solution can be calculated using the relationship between the concentration of hydronium ions ([H3O+]) and the pH and pOH values. At 25.0 °C, the relationship between pH and pOH is given by pH + pOH = 14. Given [H3O+] = 2.50 × 10^-4 M, first calculate the pH: pH = -log[H3O+] = -log(2.50 × 10^-4) ≈ 3.60. Then, calculate the pOH: pOH = 14 - pH = 14 - 3.60 = 10.4.

What Is the POH of an Aqueous Solution at 25