The Henry's law constant for helium gas in water at 30 °C is 3.70 × M/atm.When the partial pressure of helium above a sample of water is 0.400 atm,the concentration of helium in the water is ________ M. A)9.25 × 10^-4 B)1.08 × 10³ C)0.800 D)1.48 × 10^-4 E)3.70 ×

Question

Quizplus · Accepted Answer

According to Henry's law, the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid, at a constant temperature.

Mathematically, we can express this as:

C = kH * P

where C is the concentration of the gas in the liquid, kH is Henry's law constant, and P is the partial pressure of the gas above the liquid.

In this problem, we are given kH = 3.70 × 10^(-4) M/atm and P = 0.400 atm.

Substituting these values in the above equation, we get:

C = (3.70 × 10^(-4) M/atm) * (0.400 atm)

C = 1.48 × 10^(-4) M

So, the concentration of helium in the water is 1.48 × 10^(-4) M.

Therefore, the correct choice is (D).

The Henry's Law Constant for Helium Gas in Water at 30