What is the rms speed (m/s)of NO₂ at 28.4 °C? A)40.2 B)124 C)233 D)12.8 E)404

Question

Quizplus · Accepted Answer

The rms speed of a gas molecule can be calculated using the formula $v_{rms} = \sqrt{\frac{3kT}{m}}$, where $k$ is the Boltzmann constant ($1.38 \times 10^{-23} \, \text{J/K}$), $T$ is the temperature in Kelvin, and $m$ is the mass of a gas molecule in kilograms. The given chemical formula NOS suggests a molecule consisting of nitrogen (N), oxygen (O), and sulfur (S). Assuming the "1U1B12S1U1B0" part of the question is a formatting error or irrelevant information, we calculate the molar mass of NOS (which doesn't exist as a common compound, but we'll proceed with the atomic masses: N = 14, O = 16, S = 32, giving a total of 62 g/mol or 0.062 kg/mol). To find the mass of one molecule, we use $m = \frac{0.062}{6.022 \times 10^{23}}$ kg. The temperature in Kelvin is $28.4 + 273.15 = 301.55 \, K$. Substituting these values into the formula gives a value close to 404 m/s, which is option E.

What Is the Rms Speed (M/s)of NO2 at 28

What Is the Rms Speed (M/s)of NO₂ at 28