Using the Born-Haber cycle,the ΔH°f of KBr is equal to ________.
A) ΔH°f [K (g) ] + ΔH°f [Br (g) ] + I1(K) + E(Br) + ΔHlattice
B) ΔH°f [K (g) ] - ΔH°f [Br (g) ] - I1(K) - E(Br) - ΔHlattice
C) ΔH°f [K (g) ] - ΔH°f [Br (g) ] + I1(K) - E(Br) + ΔHlattice
D) ΔH°f [K (g) ] + ΔH°f [Br (g) ] - I1 - E(Br) + ΔHlattice
E) ΔH°f [K (g) ] + ΔH°f [Br (g) ] + I1(K) + E(Br) - ΔHlattice
Correct Answer:
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