What is the wavelength (nm)of light emitted when an electron in a hydrogen atom moves from n = 4 to n = 2? A)-486 B)2.06 × 10¹⁵ C)486 D)2.06 × 10⁶ E)4.86 × 10^-7

Question

Quizplus · Accepted Answer

The energy of the emitted photon can be calculated using the Rydberg formula:

1/λ = R(1/n₁² - 1/n₂²)

where n₁ = 4 and n₂ = 2, and R is the Rydberg constant.

Plugging in the values:

1/λ = (1.097 × 10⁷ m⁻¹)(1/4² - 1/2²)
     = (1.097 × 10⁷ m⁻¹)(3/16)
     = 2.179 × 10⁶ m⁻¹

Solving for λ:

λ = 4.86 × 10⁻⁷ m 
   = 486 nm

Therefore, the wavelength of the emitted light is 486 nm. Choice C is the correct answer.

What Is the Wavelength (Nm)of Light Emitted When an Electron