The frequency of a photon that has an energy of 3.7 × 10^-18 J is ________ s^-1. A)5.6 × 10¹⁵ B)1.8 × 10^-16 C)2.5 × 10^-15 D)5.4 × 10^-8 E)2.5 × 10¹⁵

Question

Quizplus · Accepted Answer

The frequency ($f$) of a photon can be calculated using the equation $E = hf$, where $E$ is the energy of the photon, $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{Js}$), and $f$ is the frequency. Rearranging the equation to solve for $f$, we get $f = \frac{E}{h}$. Substituting $E = 3.7 \times 10^{-18} \, \text{J}$ and $h = 6.626 \times 10^{-34} \, \text{Js}$, we find $f = \frac{3.7 \times 10^{-18}}{6.626 \times 10^{-34}} = 5.58 \times 10^{15} \, \text{s}^{-1}$, which rounds to $5.6 \times 10^{15} \, \text{s}^{-1}$, matching choice A.

The Frequency of a Photon That Has an Energy of 3.7