Given the data in the table below,ΔH°_rxn for the reaction 4NH₃ (g)+ 5O₂ (g)→ 4NO (g)+ 6H₂O (l) Is ________ kJ. A)-1172 B)-150 C)-1540 D)-1892 E)The ΔH°_f of O₂ (g)is needed for the calculation.

Question

Quizplus · Accepted Answer

Using the equation ΔH°rxn = ΣΔH°f(products) - ΣΔH°f(reactants), where Σ refers to the sum of all the values, we can calculate ΔH°rxn:
ΔH°rxn = [4ΔH°f(NO (g)) + 6ΔH°f(H2O (l))] - [4ΔH°f(N2H4 (g)) + 5ΔH°f(O2 (g))]
ΔH°rxn = [(4)(90.4 kJ/mol) + (6)(-285.8 kJ/mol)] - [(4)(94.6 kJ/mol) + (5)(0 kJ/mol)]
ΔH°rxn = -1168.2 kJ/mol ≈ -1172 kJ/mol (to 3 sig figs)

Given the Data in the Table Below,ΔH°rxn for the Reaction

Given the Data in the Table Below,ΔH°_rxn for the Reaction