What are the respective concentrations (M)of K⁺ and CO₃^2- afforded by dissolving 0.530 mol K₂CO₃ in water and diluting to 1.50 L? A)0.707 and 0.353 B)0.118 and 0.353 C)0.353 and 0.707 D)0.353 and 0.353 E)0.707 and 0.707

Question

Quizplus · Accepted Answer

First, let's write out the balanced chemical equation: K₂CO₃ + H2O -> K⁺ + CO₃^2- From the equation, we can see that one mole of K₂CO₃ produces one mole of each of the two products. Therefore, since we have 0.530 mol of the starting compound and we are diluting to a total volume of 1.50 L, the molarity of each product is: Molarity of K⁺ = (0.530 mol / 1.50 L) = 0.353 M Molarity of CO₃^2- = (0.530 mol / 1.50 L) = 0.353 M Therefore, the answer is (A) 0.707 and 0.353.

What Are the Respective Concentrations (M)of K+ and CO32- Afforded

What Are the Respective Concentrations (M)of K⁺ and CO₃^2- Afforded