What volume (mL)of 7.48 × 10^-2 M perchloric acid can be neutralized with 115 mL of 0.244 M sodium hydroxide? A)125 B)8.60 C)188 D)750 E)375

Question

Quizplus · Accepted Answer

The neutralization reaction between perchloric acid (HClO4) and sodium hydroxide (NaOH) can be represented as: HClO4 + NaOH → NaClO4 + H2O. This shows a 1:1 mole ratio between HClO4 and NaOH. To find the volume of HClO4 that can be neutralized, use the equation: (M1)(V1) = (M2)(V2), where M1 and V1 are the molarity and volume of the acid, and M2 and V2 are the molarity and volume of the base. Given M1 = 7.48 × 10^-2 M, M2 = 0.244 M, and V2 = 115 mL, solving for V1 gives: V1 = (M2 * V2) / M1 = (0.244 M * 115 mL) / (7.48 × 10^-2 M) = 375 mL.

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