What are the respective concentrations (M)of Fe³⁺ and I^- afforded by dissolving 0.200 mol FeI₃ in water and diluting to 725 mL? A)0.276 and 0.828 B)0.828 and 0.276 C)0.276 and 0.276 D)0.145 and 0.435 E)0.145 and 0.0483

Question

Quizplus · Accepted Answer

The dissolution of Fe(NO3)3 in water produces Fe3+ and NO3- ions. For every mole of Fe(NO3)3 dissolved, 1 mole of Fe3+ and 3 moles of NO3- are produced. Given 0.200 mol of Fe(NO3)3 and a final volume of 725 mL (0.725 L), the concentration of Fe3+ is (0.200 mol / 0.725 L) = 0.276 M. Since each mole of Fe(NO3)3 produces 3 moles of NO3-, the concentration of NO3- is 3 times that of Fe3+, which is 0.276 M * 3 = 0.828 M.

What Are the Respective Concentrations (M)of Fe3+ and I- Afforded

What Are the Respective Concentrations (M)of Fe³⁺ and I^- Afforded