Consider the reaction 2N₂O₅(g)$\rightarrow$ 4NO₂(g)+ O₂(g) Rate = k[N₂O₅] Calculate the time for the concentration of N₂O₅ to fall to one-fourth its initial value if the half-life is 133 s. A) 133 s B) 33.3 s C) 266 s D) 66.6 s E) 533 s

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Quizplus · Accepted Answer

The half-life of a reaction is the time it takes for the concentration to decrease by half. In this case, the reaction has a half-life of 133 s, which means that after 133 s the concentration of N₂O₅ will be half its initial value. To find the time it takes for the concentration to fall to one-fourth its initial value, we need to use the fact that the half-life is 133 s. We can use the following equation: t = (ln(4) / ln(2)) * 133 s t = 266 s Therefore, the time it takes for the concentration of N₂O₅ to fall to one-fourth its initial value is 266 s, which corresponds to choice C.

Consider the Reaction 2N2O5(g) →\rightarrow→ 4NO2(g)+ O2(g) Rate = K[N2O5] Calculate the Time for the

Consider the Reaction
2N₂O₅(g) $\rightarrow$ 4NO₂(g)+ O₂(g)
Rate = K[N₂O₅]
Calculate the Time for the