A nonsteroidal anti-inflammatory drug is metabolized with a first-order rate constant of 3.25day^-¹ .What fraction of the drug remains in the body after 13.0 hr? A) 0.172 B) 0.0174 C) 0.828 D) 0.873 E) 0.127

Question

Quizplus · Accepted Answer

The fraction of the drug that remains in the body after a certain time can be calculated using the first-order kinetics formula: $C = C_0 \times e^{-kt}$, where $C$ is the concentration at time $t$, $C_0$ is the initial concentration, $k$ is the rate constant, and $t$ is the time. Given that $k = 3.25 \, \text{day}^{-1}$ and $t = 13.0 \, \text{hr} = 13/24 \, \text{day}$, we can calculate the fraction remaining as $e^{-3.25 \times (13/24)}$, which approximates to 0.172.

A Nonsteroidal Anti-Inflammatory Drug Is Metabolized with a First-Order Rate