Given: 4Fe²⁺(aq)+ O₂(aq)+ 2H₂O(l)$\rightarrow$4Fe³⁺(aq)+ 4OH^-(aq) Rate = k[Fe²⁺][OH^-]²[O₂] The overall order of the reaction and the order with respect to O₂ are A) 4 and 1. B) 5 and 1. C) 3 and 1. D) 4 and 2. E) 7 and 1.

Question

Quizplus · Accepted Answer

The overall order of the reaction is the sum of the exponents of the concentrations of the reactants in the rate law. In this case, the rate law is Rate = k[Fe²⁺][OH^-]²[O₂], so the overall order of the reaction is 1 + 2 + 1 = 4. The order with respect to O₂ is the exponent of the concentration of O₂ in the rate law, which is 1.

Given: 4Fe2+(aq)+ O2(aq)+ 2H2O(l) →\rightarrow→ 4Fe3+(aq)+ 4OH-(aq) Rate = K[Fe2+][OH-]2[O2] the Overall Order of the

Given:
4Fe²⁺(aq)+ O₂(aq)+ 2H₂O(l) $\rightarrow$ 4Fe³⁺(aq)+ 4OH^-(aq)
Rate = K[Fe²⁺][OH^-]²[O₂]
the Overall Order of the