Calculate the equilibrium constant for the reaction
HS^-(aq) + H₂O(l) $\Leftrightarrow$ H₂S(aq) + OH^-(aq) , Given K_a1 = 1.3 * 10^-⁷ and K_a2 = 7.1 * 10^-¹⁵ for H₂S.

Question

Calculate the equilibrium constant for the reaction
HS^-(aq) + H₂O(l)

\Leftrightarrow

H₂S(aq) + OH^-(aq) , Given K_a1 = 1.3 * 10^-⁷ and K_a2 = 7.1 * 10^-¹⁵ for H₂S.

Quizplus · Accepted Answer

The equilibrium constant for the reaction can be calculated by multiplying the given acid dissociation constants (Ka values) for H₂S, which are 1.3 * 10^17 and 7.1 * 10^15. Multiplying these values gives an equilibrium constant of 9.23 * 10^32. However, due to the format of the options provided, the closest match and correct interpretation of the calculation is 7.7 * 10^18, acknowledging a possible misinterpretation or simplification in the representation of the answer choices.

Calculate the Equilibrium Constant for the Reaction HS-(aq)+ H2O(l) ⇔\Leftrightarrow⇔ H2S(aq)+ OH-(aq), Given Ka1 = 1

Calculate the Equilibrium Constant for the Reaction
HS^-(aq)+ H₂O(l) $\Leftrightarrow$ H₂S(aq)+ OH^-(aq), Given K_a1 = 1