Calculate the standard entropy of condensation of chloroform at its boiling point, 335 K.The standard molar enthalpy of vaporization of chloroform at its boiling point is 31.4 kJ.mol^-¹. A) -31.3 kJ.K^-¹.mol^-¹ B) +93.7 J.K^-¹.mol^-¹ C) -93.7 J.K^-¹.mol^-¹ D) +31.4 J.K^-¹.mol^-¹ E) +506 J.K^-¹.mol^-¹

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Quizplus · Accepted Answer

The standard entropy of condensation can be calculated using the formula ΔS = ΔH/T, where ΔH is the enthalpy change and T is the temperature in Kelvin. Given that the enthalpy of vaporization is 31.4 kJ/mol (which is equivalent to 31400 J/mol for conversion to Joules) and the temperature is 335 K, the entropy of condensation (which is the negative of the entropy of vaporization) is calculated as -31400 J/mol / 335 K = -93.7 J/K·mol.

Calculate the Standard Entropy of Condensation of Chloroform at Its