Calculate the final temperature when 2.50 kJ of energy is transferred as heat to 1.50 mol N₂ at 298 K and 1 atm at constant pressure. A) 75 $\circ$ C B) 159 $\circ$ C C) 80 $\circ$ C D) 82 $\circ$ C E) 92 $\circ$ C

Question

Quizplus · Accepted Answer

We can use the formula q = nCpΔT, where q is the heat absorbed, n is the number of moles, Cp is the molar specific heat at constant pressure, and ΔT is the change in temperature. We rearrange the formula to solve for ΔT:

ΔT = q / nCp

We insert the given values and constants:

ΔT = (2500 J) / (1.50 mol x 33.6 J/(mol*K))

ΔT = 52.4 K

We add this temperature change to the initial temperature:

Tf = 298 K + 52.4 K

Tf = 350.4 K = 82°C

Therefore, the correct answer is D) 82°C.

Calculate the Final Temperature When 2 ∘\circ∘ C B) 159 ∘\circ∘ C C) 80

Calculate the Final Temperature When 2 $\circ$ C
B) 159^$\circ$C
C) 80