The number of molecules in 44.8 L of nitrogen at exactly 0 $\circ$ C and 3.00 atm is
A) 1.20 * 10 24
B) 3.61 * 10 24
C) 3.61 * 10 -23
D) 2.01 * 10 23
E) 18.0 * 10 -23

Question

The number of molecules in 44.8 L of nitrogen at exactly 0 $\circ$ C and 3.00 atm is
A) 1.20 * 10 24 
B) 3.61 * 10 24 
C) 3.61 * 10 -23 
D) 2.01 * 10 23 
E) 18.0 * 10 -23

Quizplus · Accepted Answer

We can use the ideal gas equation to solve this problem:
PV = nRT
where P = 3.00 atm, V = 44.8 L, T = 273 K (0°C = 273 K) and R = 0.0821 L•atm/mol•K.
Solving for n, we get:
n = PV/RT = (3.00 atm)(44.8 L)/(0.0821 L•atm/mol•K)(273 K) = 3.61 x 10^23 molecules. 
Therefore, the best choice is B.

The Number of Molecules in 44 ∘\circ∘ C and 3

The Number of Molecules in 44 $\circ$ C and 3