Given the elements Cl, Ge,And K and three values of possible first ionization energies,418,1255,784 kJ.mol^-¹, Match the atoms with their first ionization energies. A) Cl (418), Ge (784), and K (1255 kJ.mol^-¹) B) Cl (1255), Ge (784), and K (418 kJ.mol^-¹) C) Cl (784), Ge (1255), and K (418 kJ.mol^-¹) D) Cl (1255), Ge (418), and K (784 kJ.mol^-¹) E) Cl (418), Ge (1255), and K (784 kJ.mol^-¹)

Question

Quizplus · Accepted Answer

Chlorine (Cl) has a higher first ionization energy than germanium (Ge) and potassium (K) due to its higher electronegativity and smaller atomic radius, making it harder to remove an electron. Potassium (K), being an alkali metal, has the lowest first ionization energy because it has a single electron in its outer shell that is easily removed. Germanium (Ge) falls in between Cl and K in terms of first ionization energy. Therefore, the correct match is Cl (1255), Ge (784), and K (418 kJ/mol).

Given the Elements Cl, Ge,And K and Three Values of Possible