Write the ground-state electron configuration of Fe³⁺. A) [Ar]3d⁵4s² B) [Ar]3d³4s² C) [Ar]3d³4s⁰ D) [Ar]3d⁶4s¹ E) [Ar]3d³4s³

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Quizplus · Accepted Answer

Starting with Fe, we know it has 26 electrons. The electron configuration for Fe is [Ar] 4s2 3d6. The electron configuration for S is [Ne] 3s2 3p4. The electron configuration for P is [Ne] 3s2 3p3. The electron configuration for +S is [Ne] 3s2 3p3. Therefore, the ground-state electron configuration of Fe³⁺ is: [Ar] 3d10 4s2 3p6 + [Ne] 3s2 3p3 + [Ne] 3s2 3p3 + [Ne] 3s2 3p0 Which simplifies to: [Ar] 3d10 4s2 3p6 3s2 3p3 3s2 3p0 or written out with the shorthand notation: [Ar]3d³4s². The only option that matches this electron configuration is B.

Write the Ground-State Electron Configuration of Fe3+

Write the Ground-State Electron Configuration of Fe³⁺