Write the ground-state electron configuration of Pb²⁺. A) [Xe]4f¹⁴5d⁵6s¹6p⁶ B) [Xe]4f¹⁴5d¹⁰6s² C) [Xe]4f¹⁴5d⁵6s²6p⁵ D) [Xe]4f¹⁴5d¹⁰6s¹6p¹ E) [Xe]4f¹⁴5d¹⁰6p²

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The ground-state electron configuration of Pb is [Xe]4f¹⁴5d¹⁰6s²6p². When it loses two electrons to form Pb²⁺, the electrons are removed from the 6p and 6s orbitals, resulting in [Xe]4f¹⁴5d¹⁰6s².

Write the Ground-State Electron Configuration of Pb2+

Write the Ground-State Electron Configuration of Pb²⁺