The bond order of O₂²⁺ is A) 1. B) 2. C) 3. D) 2.5. E) 1.5.

Question

Quizplus · Accepted Answer

The given molecular formula is for the ion $ O_2^{+} $. The bond order can be calculated using Molecular Orbital Theory (MOT). For $ O_2^{+} $, there are a total of 15 electrons. According to MOT, the electronic configuration will be $ \sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^1 $. This results in a bond order of $ \frac{1}{2} [8 (from bonding orbitals) - 4 (from antibonding orbitals)] = 2 $. However, because we are dealing with $ O_2^{+} $, we remove one electron, which would come from an antibonding orbital, increasing the bond order slightly to 2.5.

The Bond Order of O22+ Is

The Bond Order of O₂²⁺ Is