Write the ground-state electron configuration of Sb³⁺. A) [Kr]4d⁸5s¹5p³ B) [Kr]4d⁵5s¹5p⁶ C) [Kr]4d¹⁰5p² D) [Kr]4d¹⁰5s¹5p¹ E) [Kr]4d¹⁰5s²

Name: Write the ground-state electron configuration of Sb 3+ . A) [Kr]4d 8 5s 1 5p 3 B) [Kr]4d 5 5s 1 5p 6 C) [Kr]4d 10 5p 2 D) [Kr]4d 10 5s 1 5p 1 E) [Kr]4d 10 5s 2
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Sb has 51 electrons. Sb3+ has 51 - 3 = 48 electrons. The electron configuration of Sb is [Kr]4d105s25p3. Removing 3 electrons from Sb gives [Kr]4d105s2.

Write the Ground-State Electron Configuration of Sb3+

Write the Ground-State Electron Configuration of Sb³⁺