A 3.0-kg cylinder falls vertically from rest in a very tall, evacuated tube near the surface of the earth. What is its speed after the cylinder has fallen 6.0 m?
A)8.0 m/s
B)11 m/s
C)13 m/s
D)120 m/s
E)26 m/s

Question

Quizplus · Accepted Answer

The speed can be calculated using the equation for an object in free fall: v = sqrt(2gh), where g = 9.8 m/s² and h = 6.0 m. This gives v = sqrt(2 * 9.8 * 6) = 10.8 m/s, which rounds to 11 m/s.

A 30-Kg Cylinder Falls Vertically from Rest in a Very Tall