A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After the ice block slides 15.0 m, the force is removed. The work done by the applied force is
A)-114 J.
B)+114 J.
C)-735 J.
D)+735 J.
E)+19.7 J.

Question

Quizplus · Accepted Answer

The work done by a force is calculated using the formula: Work = Force × Distance × cos(θ). Here, the force is 7.60 N, the distance is 15.0 m, and the force is in the direction of motion (θ = 0 degrees, cos(0) = 1). Therefore, Work = 7.60 N × 15.0 m × 1 = 114 J. Since the force is in the direction of motion, the work done is positive, so the answer is +114 J.

A 500-Kg Block of Ice Is Sliding Across a Frozen Pond