A 5.0 × 10 2 -N object is hung from the end of a wire of cross-sectional area 0.010 cm 2 . The wire stretches from its original length of 200.00 cm to 200.50 cm. -What is the elongation strain on the wire? A)1.0 × 10² B)1.0 × 10^-² C)5.0 × 10² D)2.5 × 10^-³ E)4.0 × 10²

Question

Quizplus · Accepted Answer

The elongation strain is calculated as the change in length divided by the original length. The change in length is 0.50 cm, and the original length is 200.00 cm. Thus, the strain is 0.50/200.00 = 2.5 × 10^-3.

A 50 × 102-N Object Is Hung from the End of of a Wire

A 50 × 10²-N Object Is Hung from the End of of a Wire