A ball hung from a vertical spring oscillates in simple harmonic motion with an angular frequency of 2.6 rad/s and an amplitude of 0.075 m. What is the maximum acceleration of the ball? A)0.13 m/s² B)0.20 m/s² C)0.51 m/s² D)2.6 m/s² E)35 m/s²

Question

Quizplus · Accepted Answer

The maximum acceleration of an object undergoing simple harmonic motion is given by:
a_max = ω^2 * A
where ω is the angular frequency of the motion and A is the amplitude.
Plugging in the given values, we get:
a_max = (2.6 rad/s)^2 * 0.075 m
a_max = 0.51 m/s^2
Therefore, the maximum acceleration of the ball is 0.51 m/s^2, which is answer choice C.

A Ball Hung from a Vertical Spring Oscillates in Simple