Solved

How Many Kilowatt

Question 39

Multiple Choice

How many kilowatt . hours of energy are released from 25 g of deuterium How many kilowatt . hours of energy are released from 25 g of deuterium   fuel in the fusion reaction:   where the masses are   = 2.014 102 u and   = 4.002 603 u. Notes: Ignore the energy carried off by the gamma ray. Conversion factors: 1 kWh = 3.600 × 10<sup>6</sup> J; 1 eV = 1.602 × 10<sup>-</sup><sup>19</sup> J. A) 1 × 10<sup>6</sup> kWh B) 2 × 10<sup>6</sup> kWh C) 3 × 10<sup>6</sup> kWh D) 4 × 10<sup>6</sup> kWh E) 5 × 10<sup>6</sup> kWh fuel in the fusion reaction: How many kilowatt . hours of energy are released from 25 g of deuterium   fuel in the fusion reaction:   where the masses are   = 2.014 102 u and   = 4.002 603 u. Notes: Ignore the energy carried off by the gamma ray. Conversion factors: 1 kWh = 3.600 × 10<sup>6</sup> J; 1 eV = 1.602 × 10<sup>-</sup><sup>19</sup> J. A) 1 × 10<sup>6</sup> kWh B) 2 × 10<sup>6</sup> kWh C) 3 × 10<sup>6</sup> kWh D) 4 × 10<sup>6</sup> kWh E) 5 × 10<sup>6</sup> kWh where the masses are How many kilowatt . hours of energy are released from 25 g of deuterium   fuel in the fusion reaction:   where the masses are   = 2.014 102 u and   = 4.002 603 u. Notes: Ignore the energy carried off by the gamma ray. Conversion factors: 1 kWh = 3.600 × 10<sup>6</sup> J; 1 eV = 1.602 × 10<sup>-</sup><sup>19</sup> J. A) 1 × 10<sup>6</sup> kWh B) 2 × 10<sup>6</sup> kWh C) 3 × 10<sup>6</sup> kWh D) 4 × 10<sup>6</sup> kWh E) 5 × 10<sup>6</sup> kWh = 2.014 102 u and How many kilowatt . hours of energy are released from 25 g of deuterium   fuel in the fusion reaction:   where the masses are   = 2.014 102 u and   = 4.002 603 u. Notes: Ignore the energy carried off by the gamma ray. Conversion factors: 1 kWh = 3.600 × 10<sup>6</sup> J; 1 eV = 1.602 × 10<sup>-</sup><sup>19</sup> J. A) 1 × 10<sup>6</sup> kWh B) 2 × 10<sup>6</sup> kWh C) 3 × 10<sup>6</sup> kWh D) 4 × 10<sup>6</sup> kWh E) 5 × 10<sup>6</sup> kWh = 4.002 603 u. Notes: Ignore the energy carried off by the gamma ray.
Conversion factors: 1 kWh = 3.600 × 106 J; 1 eV = 1.602 × 10-19 J.


A) 1 × 106 kWh
B) 2 × 106 kWh
C) 3 × 106 kWh
D) 4 × 106 kWh
E) 5 × 106 kWh

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents