How many mL of 0.100 M NaOH are needed to neutralize 24.0 mL of 0.150 M HCl?
A)12.0 mL
B)18.0 mL
C)24.0 mL
D)36.0 mL
E)48.0 mL

Question

Quizplus · Accepted Answer

To neutralize the HCl solution, the moles of HCl must equal the moles of NaOH. The moles of HCl are calculated as (0.150 M)(0.0240 L) = 0.00360 moles. Since the reaction between NaOH and HCl is 1:1, we need 0.00360 moles of NaOH. The volume of NaOH required is (0.00360 moles) / (0.100 M) = 0.0360 L, which is 36.0 mL.

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